The acceleration due to gravity at a height (1/20) th the radius of the earth above earth’s surface is 9 m/s 2 . Find out its approximate value at a point at an equal distance below the surface of the earth.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
m/s 2 = 9.5 m/s 2
Sol. Field outside shell g 1 = g 
So, 9 = g 
⇒ 
Field inside shell E = g 
E = 10 
E = 10 – 0.5 = 9.5 m/sec 2
Solving we get x ≈ 9.5 m/s 2
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